It is important that each of the simplified beam sections (subbeams) are in
the
appendix
(or handbook). This beam has been split into three subbeams: 1)
cantilever with a point load, 2) cantilever with a moment load, and 3) cantilever
with a distributed load. (The beam could be split into other subbeam combinations.)
Notice that the beam loading has also been distributed to the subbeams. The
equivalent loading for the uniform distributed load on the right subbeam is
P = [(0.04 N/mm^{2})(12 mm)] (50
mm)
= (0.048 N/mm)(50 mm) = 24
N
M = F d
= [(0.04 N/mm^{2})(12
mm)(50 mm)] (25 mm)
= [24 N] (25 mm) = 600
Nmm
These loads are also the internal shear and moment at the joint between the
subbeams.
Subbeam 3) is modeled as a cantilever beam since its deflection will
be in additional to the deflection of the right beam section. The total deflection
will be
v_{total} =
v_{P} +
v_{M} +
v_{w} + θ_{P} L
+ θ_{M} L
The δ terms are straight forward and simply added together.
The right beam also rotates (θ_{P} + θ_{M})
at its tip due to the point load,P, and moment load, M. These rotations will
cause added deflection for the left subbeam.
