 Ch 4. Particle Momentum and Impulse Multimedia Engineering Dynamics Impulse & Momentum Consv. Linear Momentum Impact AngularMomentum MassFlow
 Chapter - Particle - 1. General Motion 2. Force & Accel. 3. Energy 4. Momentum - Rigid Body - 5. General Motion 6. Force & Accel. 7. Energy 8. Momentum 9. 3-D Motion 10. Vibrations Appendix Basic Math Units Basic Equations Sections Search eBooks Dynamics Fluids Math Mechanics Statics Thermodynamics Author(s): Kurt Gramoll ©Kurt Gramoll DYNAMICS - EXAMPLE Collision of Two Balls Example Two balls, A and B, impact each other as shown. If the coefficient of restitution, e, is 1.0 (perfectly elastic), what is the velocity magnitude of ball B after impact? Solution Velocity of Balls Before and After Collision Ball B only has a velocity in the y-direction, so first consider y-direction momentum. Conservation of momentum before and after impact gives      mAvA1y + mBvB1y = mAvA2y + mBvB2y      4 cos30 - 3 = -vA2y + vB2y      0.4641 = -vA2y + vB2y There are still unknowns, so the impact equation needs to be used,      e = (vB2y - vA2y)/(vA1y - vB1y)      1 = [vB2y - (-vA2y)] / [4 cos30 - (-3)]      3.464 + 3 = vB2y + vA2y      6.464 = vB2y + vA2y Combining both equations      0.4641 = -(6.464 - vB2y) + vB2y      0.4641 + 6.464 = 2vB2y      vB2y = 3.464 m/s vB2y = vB2 = 3.464 m/s

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