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A 5 kg collar slides along a rod that is rotating. The collar is also attached to the center with a spring. There is friction between the collar and the bar, μ = 0.3. At a particular time, dθ/dt = 1.2 rad/s, dr/dt = 0.9 m/s, d2r/dt2 = 1.3 m/s2, and r = 0.7 m. The angular velocity is constant. What is the force magnitude acting on the collar due to the spring? Neglect gravity. |

Collar Free-body Diagram
with Accelerations |
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The acceleration in the radial and theta directions need to be determined before summing forces. The given information is,

Substituting into acceleration equations,

Summing forces and accelerations give,
ΣF = maθ
N = 5 (2.16)
N = 10.8 N
ΣF = mar
-Fs - Ff = mar
-Fs - μN = 5 (0.292)
-Fs - 0.3 (10.8) = 1.46
Fs = -4.70 N or 4.70 N
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