The water will cause a pressure on the wall which is a linear function of the
depth. The pressure on the wall will be
p = h g ρ
where ρ is the water density and g is the gravitational constant, 9.81 m/s^{2}. The maximum pressure will be at the bottom, h = 3 m,
p = (3 m) (9.81 m/s^{2}) (1 g/cm^{3})
= (3 m) (9.81 kN/m^{3}) = 29.43 kN/m^{2}
The pressure now needs to be converted to a distributed load on a typical vertical
beam. There is one beam for every 2 meters, so the maximum distributed load at the
bottom is
w_{max} = (29.43 kN/m^{2} )(2 m) = 58.86 kN/m |