The pliers fall from the top of a 574 feet tower. Its
position is described by s = 16t^{2}. What is the velocity when
the pliers falls 1 second and what is the velocity when the pliers reaches
the ground?

First, find the velocity in terms of t seconds

Diagram of s = 16t^{2}

At 1 seconds,

v(t = 1) = 16 feet/second

Next, find the how many seconds (t_{g}) it takes
for the pliers need to reach the ground.

574 = 16t^{2}

t_{g} = 5.99 second

Thus the velocity of pliers to reach the ground is:

v(g) = 16t_{g} =
95.8 feet/second

Discussion

Velocity and Acceleration

The velocity of the pliers is calculated by the method
of limit. Is it possible to calculate the acceleration? The answer is
yes. Using

In other words, the slope of the tangent line of the v-t curve at a
specific point equals to the acceleration at that point.