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MATHEMATICS - CASE STUDY SOLUTION

 

The probability that the electron will be found within a spherical volume of radius 3a needs to be determined ( a is a constant).

     

The Probability density Function p(r)
 

The probability function is:

      

The integration by parts formula is given as

      

To integrate this function, Consider u = x2 and
dv = e-2x/adx. Then du = 2xdx and v = -a/2e-2x/a

     
 


     

The Probability Function P(r)
 

Use integration by parts again to determine the second term of the above expression.

Let u = x and dv = e-2x/adx, then du = dx and
v = -a/2e-2x/a
     

Substituting this expression into the expression of P(r) gives

      

Therefore,

      P(3a) = 1 - (18 + 6 +1)e-6 = 0.938

That means the electron has 93.8% chance to be found within a sphere of 3a radius.