Consider the heat recovery system as a control volume and denote the
hot air inlet as 1, hot air exit as 2, cold water inlet as 3, and hot water exit as 4, shown on the left.
(1) Determine the mass flow rate of the cold water
The energy balance for a control volume is:
According to the assumptions, the energy balance can be simplified to
Water is modeled as an incompressible substance. Thus, its enthalpy equals
h4 = cwT4 and h3 = cwT3
Exhausted air is modeled as an ideal gas, its enthalpy equals
h2 = cPaT2 and h1 = cPaT1
where T1,T2, T3 , T4 and
are given as
T1 = 60oC = 333 K
T2 = 35oC = 308 K
T3 = 25oC = 298 K
T4 = 50oC = 323 K
=
200 kg/s
Substituting all the data to the energy balance gives the mass flow rate of cold water.
(2) Determine the exergy destruction of the heat recovery system
The exergy balance of control volume undergoing a steady-flow process is
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