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THERMODYNAMICS - CASE STUDY SOLUTION


 

Ann turns on her fan trying to cool her room while she is gone. The room temperature when she comes back in the evening needs to be determined.

Assumptions:

  • Consider the air as an ideal gas
  • All the doors and windows are tightly closed
  • Disregard any heat transfer through the walls and the windows
  • The room pressure remains at 1 atm
     

Simplification of the
Energy Balance Equation
 

The system is a closed system since all the doors and windows are tightly closed. It is a stationary system by disregarding the changes of the velocity and elevation of air during the cooling process. The energy balance for this system is:

      Q - W = U2 - U1

Also, the assumption indicates that the heat transfer through the walls and windows is disregarded, hence no heat transfer to or from this system.

      Q = 0

The electric energy is transferred into the system by the fan, hence this work is negative.

      W = -fant

For an ideal gas, the internal energy is a function of the temperature. If the specific heat at the average room temperature is used, the difference of internal energy is:

      U2 - U1 = cv,av(T2 - T1)

The energy equation for the air in the room becomes:

      fant = cv,avm(T2 - T1)

      T2 = fant/cv,avm + T1

Ann leaves at 8:00 in the morning and returns at 6:00 in the evening. Hence the total time is 10 hours.

The average value of specific heat is used to calculate the temperature. A room temperature is assume first. Then iteration is used till a reliable result obtained. Assume the room temperature is 55 oC when she is back in the evening.

      Tav = (15 + 55)/2.0 = 35 oC

At 1 atm and 35 oC, the density of the air is ρ = 1.166 kg/m3. The mass of the air in the room is:

      m = (4)(6)(6)(1.166) = 167.9 kg

     
Specific Heats of Some Common
Ideal Gases
 

From table, at 35 oC, the constant volume specific heat is
      cv,av = 0.718 kJ/(kg-K) = 718 J/(kg-K).

With all the data known,

      T2 = (150)(10)(3600)/((718)(167.9) + 15 = 59.8 oC

      Tav = (15 + 59.8)/2.0 = 37.4 oC

The calculated average temperature is pretty close to 35 oC (the assumed temperature), hence no iteration is needed.

As a result, it looks like Ann's dream of a cooler room in the evening is impossible after all.