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THERMODYNAMICS - CASE STUDY SOLUTION

   

A piston-cylinder device is used to vaporize saturated liquid to saturated vapor under 100 kPa. The volume change and the amount of energy added need to be determined.

Assumptions:

  • The pressure is kept as a constant during the process
     


Volume Change Vg - Vf

 

(1)Volume change

The total volume of the saturated liquid

      Vf = vfm

The total volume when all the water becomes saturated vapor.

       Vg = vgm

The volume difference is:

      Vdifference = vgm - vfm

                     = 10 (1.673 - 0.001) = 16.72 m3

(2) Amount of energy added

Latent heat of vaporization of water under 100 kPa is LV = 2257.0 kJ/kg. It is the same amount of energy needed to change 1 kg saturated water to saturated vapor under 100 kPa.

      Q = m Lv = 10 (2257.0) = 22570 kJ