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MATHEMATICS - THEORY

   

Mean Value Theorem and its geometry meaning are discussed in this section.

     
    Mean Value Theorem
   

In the previous section, Rolle's theorem was introduced. One of the prerequisite of that theorem is the two endpoints value are equal. However, the mean value theorem does not have this requirement. It is more general than the Rolle's theorem. The mean value theorem states that if a function satisfies the following two hypotheses,

  • the function is continuous on the closed interval [a, b],
  • the function is differentiable on the open interval (a, b),

then there is a point c in the open interval (a, b) such that

                                        (1)

     


Mean Value Theorem
Explanation Graphic


Multiple Parallel Line

 

Rearranging this equation gives:

                             (2)

Now consider the slope of the line AB,

     mAB = tanα = (f(b)-f(a))/(b-a)                          (3)

The right hand side of the equation (1) and (3) are equal. Since the left hand side of equation (1) is the slope of the tangent line at point C, the mean value theorem means that there is a pont C where the tangent line is parallel to the line AB.

If a function satisfies the hypotheses of the mean value theorem, it may have multiple function tangent lines that are parallel to the secant line AB.

The mean value theorem is important because it sets some basic facts in differential calculus. One of these basic facts is the following theorem.

     
    Theorem Related to Constant

Velocity is Constant
 

One of the example in Rolle's Theorem is a car driving at an uniform speed, its acceleration is 0. It can also be stated that if a car has zero acceleration, then its velocity is uniform. This is true in the physics, and it is an example of how the theorem works. The theorem states:

If the derivative of a function at all points are 0 in an open interval (a, b), then the function is constant on (a, b).

Is there any case that this theorem fails? Consider another example,

     

The function is obviously not a constant. Does theorem fail in this function? The answer is no. Since when x equals 0, this function is not differentiable. In (0, +∞) and ( -∞, 0) the function are constant.