First, take an arbitrary location, r, on
[R, R + h], as shown
on the left. The force applied to overcome the gravitational force
is the same as the attractive force between the earth and the satellite
at that location.
F = Gmems/r2
When the satellite moves from r to r + dr, work done by this force is
dW = Fdr = Gm1m2/r2 dr
Move the satellite from the earth surface ( r = R) to its orbit ( r
= R + h) equals
Substituting the given value into the above equation gives
R + h = 6.37 x 106 +
650 x 103 =
7.02 x 106 m
W = 6.67 x 10-11(5.98
x 1024)(173)(650
x 103)
/((7.02
x 106)(6.37 x 106)
= 1,003 MW
To move the satellite vertically to its orbit, requires 1,003 MW of
work. This does not include work needed to move the rocket used to launch the satellite. |