The schematic of the power plant is shown on the left. Take the pipes
and the turbines together as a control volume. Denote the inlet of the
intake pipes as 1 and the outflow of the turbine as 2.The reversible
steady-flow work generated by this power plant is
where
The first term on the left-hand side is the pressure term. Point 1 is located 5 meter under the water surface in reservoir. So pressure P1
is
P1 = ρgh + Patm= 1000(9.8)(5) + 100,000
= 149,000 Pa = 1.49 bar
Point 2 is located at the outflow of the power plant. Its pressure equals the ambient pressure,
P2 = 1.0 bar
The second term on the left-hand side is the kinetic energy term. Water enters the pipes with a velocity of 1 m/s and leaves the turbine as the
same velocity. Hence, there is no kinetic energy change when water flows from point 1 to point 2. That is,
ΔKE = 0
The third term on the left-hand side is the potential energy term. Water flowing from point 1 (100 m higher than point 2) to point 2 experiences a potential energy change of
Substituting the three terms into the expression for reversible steady-flow work gives
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