The submarine model is built with a scale of 1:10. That is, Lp/Lm =
10
Since submarines usually cruise well below the water surface, the Froude
number is not important in this study. In addition, it is assumed that
the compressibility
effects are negligible, hence the Mach number has no role in this
study as well. In order for dynamic similitude, both the Reynolds number
and dimensionless drag should be identical for the model and prototype.
The Reynolds number for the prototype is calculated as
Rep = ρpVpLp/μp =
(1,030)(4)(10Lm)/(1.2)(10-3)
=
34.3×106 Lm
From the properties table of water, the viscosity and density of fresh
water at a temperature of 40oC are 0.7×10-3 N-s/m2 and
992 kg/m3, respectively.
Equate the Reynolds number for the prototype and model and rearrange
terms to yield an expression for the model's velocity
Rem = Rep
ρmVmLm/μm
= 34.3×106 Lm
992 Vm / 0.7×10-3= 34.3×106
Vm = 24.2 m/s
Now, equating the dimensionless drag force for the prototype and model yields
In this problem, it was assumed that both the Re and dimensionless drag force relationship where known. They could have been derived using the Buckingham Pi Theorem. |