(1) Determine the maximum thermal efficiency
Assuming the power plant is a Carnot heat engine, which works between
a source at temperature 85 oC, and a sink at temperature 35 oC.
ηth,rev =
1 - (35+273)/(85+273) = 14%
(2) Determine the maximum power generated by the pond
The definition of the thermal efficiency of a heat engine is
ηth =
Wnet,out/Qin
Rearranging this equation gives
Wnet,out = Qin ηth
If the efficiency of this heat engine equals the Carnot efficiency,
and the heat absorbed by the salt water is totally input to the heat
engine, the output net work can achieve its maximum value.
Wnet,max = QHηth,rev
The bottom area of the pond is
Apond = (10) (10) = 100
m2
Heat absorbed by the salt water in the pond bottom area is
QH = (0.3) (100) = 30
kW
Hence, the maximum net work output by the heat engine equals
Wnet,out,max = Qin ηth,rev =
( 30)(0.14) = 4.2 kW
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