Ice Melt in Hot Water
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In nature, processes occur in a certain
direction, and not in the reverse direction. For example, if a block
of ice is put into a cup of hot water, the ice will melt
and the temperature of the water will decrease as a result of heat transferred
from the higher
temperature water to the lower temperature ice. This process is satisfied
the first law of thermodynamics, which requires the energy lost by
the water equals the energy gained by the ice.
Consider the reverse process. A block of ice is put into
a cup of hot water. Heat is transferred from the ice to the water. As
a result, the water temperature increases and the ice temperature decreases. This process
still obeys the first law. That is, the energy lost by the block of
ice equals the energy gained by the water. But this process never
occurs.
This example shows that if a process only satisfies the first
law, it may not occur. Hence, another law must also be obeyed
to guarantee a process
to happen. This is the second law of thermodynamics. A process will
not occur unless it satisfies both the first and the second laws
of thermodynamics.
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Clausius Statement of the Second Law |
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The Clausius statement of the second law states
It is impossible for any system to operate
in such a way that the sole result would be an energy transfer
by heat from a cooler to a hotter body.
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Heat can transfer from a cooler body to a hotter body if other
effects accomplishing the heat transfer occur within the system or its
surroundings, or both. Air conditioners and refrigerators are devices
to transfer heat from a cool space to its hot surroundings. But
both of them need power input. The Clausius statement says that an air
conditioner cannot cool a room without power input.
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Kelvin-Plank Statement of the Second Law
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A
heat engine must reject some energy to a heat sink in order to run a cycle. That is, no heat engine can convert all the heat it received from a high-temperature source to work. It is the basis for the Kelvin-Planck statement of the second law of thermodynamics, which is
It is impossible for any system to operate
in a thermodynamic cycle and deliver an equivalent amount of
work to its surroundings while receiving energy by heat transfer
from a single thermal reservoir. |
The Kelvin-Planck statement puts forward the idea that no heat engine can
have 100 percent efficiency. It must exchange heat with a low-temperature
heat sink as well as a high-temperature source to complete the thermodynamic
cycle.
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Any Device that Violates the
Kelvin-Plank Statement also
Violates the Clausius Statement
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Consider two devices A and B working between a high-temperature
reservoir and a low-temperature reservoir. Device A is assumed to transfer
Heat (QA,H) to work ( WA, net) and have
100 percent efficiency. That is,
WA, net = QA,H
Device A violates the Kelvin-Planck statement.
Device B is a heat pump which receives heat (QB,L) from
the low-temperature reservoir, receives work (WA, net) from
device A and rejects the total energy of WA,
net and
QB,L to
the high-temperature reservoir. Heat rejected by device C, which is
the combination of devices A and B, to the high-temperature reservoir
equals
(QB,L + WA,net)
- QA,H
= (QB,L + WA, net) - WA, net
=
QB,L
Device C receives heat (QB,L) from the low-temperature
reservoir and rejects the same amount of heat (QB,L) to
the high-temperature reservoir. It violates the Clausius statement.
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Any Device that Violates the
Clausius Statement also Violates
the Kelvin-Plank Statement
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It can also be shown in a similar way that if a device violates the Clausius
statement, it also violates the Kelvin-Planck statement. Hence, the Clausius statement and the Kelvin-Planck statement are two equivalent
expressions of the second law of thermodynamics.
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