Angular momentum is analogous to the principle of
impulse and momentum. The angular momentum about a point (generally the origin, O) is
The distance vector, r, is from the point of rotation to the object. This cross product will produce a vector, H, that is perpendicular to both r and v, as shown in the diagrams at the left.
Most problems deal with the angular momentum for an object moving in the x-y plane (about the origin O). Then the angular momentum equation simplifies to
Ho = m|r||v|
sinθ
ez
where r is the position vector of the object and ez is the unit vector in the z direction.
The relationship between the angular momentum of an object and the external moment applied to the object can be determined by examining the cross product of the position vector and Newton's Second Law, or
r ×
ΣF = r ×
ma = r × m dv/dt
The right-hand side of the this equation equals the time derivative of the angular momentum,
d(r ×
mv)/dt = (dr/dt ×
mv) + (r × m
dv/dt)
=
(v × mv) + (r
× m dv/dt)
=
r × m dv/dt
Thus, the moment of external forces about O equals the object's rate
of change of angular momentum about O:
Integrating this equation with respect to time gives
If the moment acting on an object about a fixed point O is known, it can be integrated to determine the object's change in angular momentum.
If the moment is zero, Ho is constant, i.e. angular momentum is conserved.
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