Ball B only has a velocity in the y-direction, so first consider y-direction momentum. Conservation of momentum before and after impact gives
mAvA1y + mBvB1y = mAvA2y
+
mBvB2y
4 cos30 - 3 = -vA2y + vB2y
0.4641 = -vA2y + vB2y
There are still unknowns, so the impact equation needs to be used,
e = (vB2y - vA2y)/(vA1y - vB1y)
1 = [vB2y - (-vA2y)] / [4 cos30 - (-3)]
3.464 + 3 = vB2y + vA2y
6.464 = vB2y + vA2y
Combining both equations
0.4641 = -(6.464 - vB2y) + vB2y
0.4641 + 6.464 = 2vB2y
vB2y = 3.464 m/s
vB2y = vB2 = 3.464 m/s
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