The moment of the force about joint B is given by
MB
= rBQ ×> F
The cross product in determinant form is
Expanding the equation gives
MB = (rBQy Fz
- rBQz Fy)i + (rBQz Fx
- rBQx Fz)j
+ (rBQx Fy - rBQy Fx)k
Substituting the appropriate values and simplifing to determine the
moment at joint B gives
MB = (2,400 + 3,600 sinα)i
+
(3,600 cosα)j + (3,600 sinα)k
If the magnitude of MB is plotted as a function of
the angle α, then the moment is a maximum
at
α = 90°, with a value of 6,997 N-cm or about 70 N-m. This
is approximately 62% greater than the moment at α
= 0°.
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