Rain falls at: i = 2 cm/hr = 0.02 m/hr over
an area of
A = 1 km2 = 1,000,000 m2
Infiltration rate: 1 cm/hr = 0.01 m/hr
A small channel causes runoff = 0.01 m3/s = 36 m3/hr
For ponding, rainfall must exceed infiltration plus runoff (conservation of mass for a constant density fluid)
rainfall volume
= (rainfall intensity)(area) = iA
= (0.02)(1,000,000)
= 20,000 m3/hr
infiltration volume + runoff volume
= (0.01)(1,000,000) + 36
= 10,036 m3/hr
Since rainfall volume > (infiltration volume + runoff volume), ponding will occur at a rate of (20,000 - 10,036) = 9,964 m3/hr
Note: system is not at steady state. For it to be at steady state, the outflow would need to increase to 10,000 m3/hr, at which point there would be zero ponding. |