The system is a closed system since all
the doors and windows are tightly closed. It is a stationary system
by disregarding the changes of the velocity and elevation of air during
the cooling process. The energy balance for this system is:
Q - W = U2 - U1
Also, the assumption indicates that the
heat transfer through the walls and windows is disregarded, hence
no heat transfer to or from this system.
Q = 0
The electric energy is transferred into the system by the fan, hence
this work is negative.
W = -fant
For an ideal gas, the internal energy is a function of the temperature.
If the specific heat at the average room temperature is used, the difference
of internal energy
is:
U2 - U1 = cv,av(T2 - T1)
The energy equation for the air in the room becomes:
fant
= cv,avm(T2 - T1)
T2 = fant/cv,avm
+ T1
Ann leaves at 8:00 in the morning and returns at 6:00 in the evening.
Hence the total time is 10 hours.
The average value of specific heat is used to calculate the temperature.
A room temperature is assume first. Then iteration is used till
a reliable result obtained. Assume the room temperature is 55 oC
when she is back in the evening.
Tav = (15 + 55)/2.0 = 35 oC
At 1 atm and 35 oC, the density of the air is ρ =
1.166 kg/m3. The mass of the air in the room is:
m = (4)(6)(6)(1.166) = 167.9 kg
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