This problem involves loading from two directions, and thus requires at least the 2-D Hooke's Law. The 3-D Hooke's Law could be used, but since σz is zero, those equations will reduce to the 2-D equations. The equations are,
εx = (σx - ν σy)/E
εy = (σy - ν σx)/E
The strains and stresses in the x and y direction need to be calculated.
σx = Px/Ax = 5/[(0.05)(0.005)]
= 20 MPa
σy = Py/Ay = 9/[(0.10)(0.005)]
= 18 MPa
εx = 0.021/10 = 0.0021 cm/cm
εy = 0.009/5 = 0.0018 cm/cm
Substituting the stresses and strains into the 2-D Hooke's Law equations, gives
0.0021 E = 20 - ν 18
0.0018 E = 18 - ν 20
Solving for ν gives,
ν =
0.1876 |