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DYNAMICS - CASE STUDY SOLUTION

 

  Solution of a)


Arm motion from 0 ≤ t ≤ 1 seconds

 

Take the time derivative of the position to get an equation for the velocity as a function of time:

     v(t) = dx(t)/dt = d(0.3 t2 - 0.2 t3)/dt

     v(t) = 0.6 t - 0.6 t2 m/s

 

     

Arm motion from 1≤ t ≤ 1.5 seconds
  Solution of b)

 

Take the time derivative of the velocity to get an equation for the acceleration as a function of time:

     a(t) = dv(t)/dt = d(0.6 t - 0.6 t2 )/dt

     a(t) = 0.6 - 1.2 t m/s2

     

Position-Velocity-Acceleration Curve Relationships
     
   
 
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